XXXXXXXXXX:45 CR i SE VT YC = CK SN POY OL SIIQUONA {5 Wonurod se0 pouwrsw PUL Isp 0X Sv Gum 0S 5...

Question

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Aakashgoyal · Accepted Answer

solution
Q1. A particle at charge -4mC and mass 2 grams starts at point (1,1,1) with a velocity of 5ay m/s in a
magnetic field B=16ax Wb/m². Determine the position and velocity of the particle after 5 seconds.
Describe the motion of the charge.
Ans:
Given:
q= -4mC = -4x10-3 C
m= 2 gm = 2x10-3 kg
V= 5ay m/s
B= 16ax Wb/m2
We know that,
?
→
= ? ?
→
× ?
→( )
that is,
?
→
=− 4 × 10−3 ×5 ×16× ?
?
× ?
?( )
Therefore,
?
→
= ??
→
= 0. 32?
?
 ?
And,
?
→
=
0.32?
?
2 × 10−3
= 160?
?
 ?/?
Now distance d can be calculated as:
? = 12 ??
2 = 12 ×160×5
2 = 2000?
?
 ?
Since the particle was initially at (1,1,1) and is travelling in positive z-direction,

every thing is attached

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