A ball is thrown across a playing field from a height of h = 5 ft above the ground at an angle of...

Question

A ball is thrown across a playing field from a height of h = 5 ft above the ground at an angle of 45° to the horizontal at the speed of 20 ft/s. It can be deduced from physical principles that the path of the ball is modeled by the function
y = − 32/(20)2 x2 + x + 5
where x is the distance in feet that the ball has traveled horizontally.
 
(a) Find the maximum height attained by the ball.
(b) Find the horizontal distance the ball has traveled when it hits the ground. (Round your answer to one decimal place.)

Ajay · Accepted Answer

Given: Path function y = ? 32 /(20)^2 . x2 + x + 5, where x is the distance in feet; Height (h) = 5 ft above the ground; Angle = 45° to the horizontal and speed = 20 ft/s.
u 20 ft s
u cosE
5fts
(a) It is known that during the jounrey in air, the horizontal speed (u cos theta )remains the same.

A ball is thrown across a playing field from a height of h = 5 ft above the ground at an angle of 45° to the horizontal at the speed of 20 ft/s. It can be deduced from physical principles that the...

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